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For the modulated signal x(t) = m(t) cos{2nfct), the message signal m(t) = 4cos(1000πt) and the carrier frequency fc is 1 MHz. The signal x(t) is passed through a demodulator, as shown in the figure below. The output y(t) of the demodulator is
  • a)
    cos(1000πt) 
  • b)
    cos(540πt) 
  • c)
    cos(920πt)
  • d)
    cos(460πt)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For the modulated signal x(t) = m(t) cos{2nfct), the message signal m(...
Output of multiplier
= x(t) cos2π(fc + 40)t = m(t) cos2πfct.cos2π(fc + 40)t

Given, m(t) = 4cos1000πt
So, output of multiplier = = cos2π(2fc + 540)t + cos2π(2fc-460)t + cos2π(540)t+ cos2π(460)t
Output of Low pass filter
= cos [2π(460)]t
= cos 920 πt
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For the modulated signal x(t) = m(t) cos{2nfct), the message signal m(t) = 4cos(1000πt) and the carrier frequency fc is 1 MHz. The signal x(t) is passed through a demodulator, as shown in the figure below. The output y(t) of the demodulator isa)cos(1000πt)b)cos(540πt)c)cos(920πt)d)cos(460πt)Correct answer is option 'C'. Can you explain this answer?
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For the modulated signal x(t) = m(t) cos{2nfct), the message signal m(t) = 4cos(1000πt) and the carrier frequency fc is 1 MHz. The signal x(t) is passed through a demodulator, as shown in the figure below. The output y(t) of the demodulator isa)cos(1000πt)b)cos(540πt)c)cos(920πt)d)cos(460πt)Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For the modulated signal x(t) = m(t) cos{2nfct), the message signal m(t) = 4cos(1000πt) and the carrier frequency fc is 1 MHz. The signal x(t) is passed through a demodulator, as shown in the figure below. The output y(t) of the demodulator isa)cos(1000πt)b)cos(540πt)c)cos(920πt)d)cos(460πt)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the modulated signal x(t) = m(t) cos{2nfct), the message signal m(t) = 4cos(1000πt) and the carrier frequency fc is 1 MHz. The signal x(t) is passed through a demodulator, as shown in the figure below. The output y(t) of the demodulator isa)cos(1000πt)b)cos(540πt)c)cos(920πt)d)cos(460πt)Correct answer is option 'C'. Can you explain this answer?.
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